diff --git a/types/js-combinatorics/index.d.ts b/types/js-combinatorics/index.d.ts
index 6a5fa8e249..702ef1f9a2 100644
--- a/types/js-combinatorics/index.d.ts
+++ b/types/js-combinatorics/index.d.ts
@@ -1,4 +1,4 @@
-// Type definitions for js-combinatorics v0.5.0
+// Type definitions for js-combinatorics v0.5.4
 // Project: https://github.com/dankogai/js-combinatorics
 // Definitions by: Vasya Aksyonov <https://github.com/outring>
 // Definitions: https://github.com/DefinitelyTyped/DefinitelyTyped
@@ -92,6 +92,14 @@ declare namespace __Combinatorics {
 	 */
 	function combination<T>(a:T[], n?:number):IGenerator<T[]>;
 
+	/**
+	 * Generates the combination of array with n elements, which
+	 * also supports larger sets of elements.
+	 * When n is ommited, the length of the array is used.
+	 * Somewhat slower than combination()
+	 */
+	function bigCombination<T>(a:T[], n?:number):IGenerator<T[]>;
+
 	/**
 	 * Generates the permutation of array with n elements.
 	 * When n is ommited, the length of the array is used.
diff --git a/types/js-combinatorics/js-combinatorics-tests.ts b/types/js-combinatorics/js-combinatorics-tests.ts
index 68714ca17a..4162515bc2 100644
--- a/types/js-combinatorics/js-combinatorics-tests.ts
+++ b/types/js-combinatorics/js-combinatorics-tests.ts
@@ -25,6 +25,15 @@ const filteredCombinations:string[][] = combination.filter((i:string[]) => i.len
 const allCombinations:string[][] = combination.toArray();
 const combinationsCount = combination.length;
 
+const limitedBigCombination = Combinatorics.bigCombination(["a", "b", "c"], 2);
+const bigCombination = Combinatorics.bigCombination(["a", "b", "c"]);
+const nextBigCombination:string[] = bigCombination.next();
+bigCombination.forEach((i:string[]) => console.log(i));
+const bigCombinationsLengths:number[] = bigCombination.map((i:string[]) => i.length);
+const filteredBigCombinations:string[][] = bigCombination.filter((i:string[]) => i.length > 0);
+const allBigCombinations:string[][] = bigCombination.toArray();
+const bigCombinationsCount = bigCombination.length;
+
 const limitedPermutation = Combinatorics.permutation(["a", "b", "c"], 2);
 const permutation = Combinatorics.permutation(["a", "b", "c"]);
 const nextPermutation:string[] = permutation.next();